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Proof step 1 from proof sum-countFun-sub (conclusion)

⊦ 0 ≤ i → Σ countFun(i, j, intfun) - Σ countFun(i, j, intfun0) = Σ countFun(i, j, λ i0. intfun(i0) - intfun0(i0))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs%sub-eq: ⊦ i - j = i0 ↔ i = i0 + j; from specification int-abs