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Proof step 10 from proof sum-in-not-ls (previous step)

i0 < 0, 0 ≤ i, Σ ints0 < j, i0 ∈ ints0, i + Σ ints0 < j, j ∈ ints0, ∀ i0. i0 ∈ ints0 → 0 ≤ i0, ∀ j0. ¬ j0 ∈ ints0 ∨ ¬ Σ ints0 < j0 ∨ (∃ i. ¬(i ∈ ints0 → 0 ≤ i)) ⊦

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 7 terms: i0

Additional information

Used simplifier rules: lels-03: ⊦ i < j → (¬ ¬ j ≤ i ↔ false); from specification int-abs Used terms: i0