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Proof step 12 from proof add-ones-grlen-02 (previous step)

1 < # bits ∧ 1 < # bits0, # bits0 ≤ # bits, ∀ bits, bits1. # bits1 < # bits0 → # bits1 ≤ # bits → bits1 = [] ∨ bitsand(bits, bits1) = bits1 ∨ false ∈ bits ∨ bits1.first ⊦ bitsand(bits.butlast, bits0.butlast) + (bits.last ∧ bits0.last) = bits0, bits0 = [], bits0.first, false ∈ bits

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 13:
# bits0 ≤ # bits, ∀ bits, bits1. # bits1 < # bits0 → # bits1 ≤ # bits → bits1 = [] ∨ bitsand(bits, bits1) = bits1 ∨ false ∈ bits ∨ bits1.first ⊦ bits0 = [], bitsand(bits.butlast, bits0.butlast) + (bits.last ∧ bits0.last)' = bits0, # bits = 1, bits = [], # bits0 = 1, bits0.first, false ∈ bits

Rule argument

Additional information

Used simplifier rules: ⊦ # bits = 0 ↔ bits = [];% ⊦ 1 < m ↔ ¬(m = 0 ∨ m = 1);% ⊦ bits + boolvar = bits + boolvar ';