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Proof step 2 from proof add-ones-lelen (previous step)

true, ∀ bits1, bits. # bits1 < # bits0 → true → ¬ false ∈ bits ∧ # bits ≤ # bits1 ∧ bits ≠ [] → bitsand(bits, bits1) = bits1 ⊦ ¬ false ∈ bits ∧ # bits ≤ # bits0 ∧ bits ≠ [] → bitsand(bits, bits0) = bits0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
# bits ≤ # bits0, ∀ bits1, bits. # bits1 < # bits0 → true → ¬ false ∈ bits ∧ # bits ≤ # bits1 ∧ bits ≠ [] → bitsand(bits, bits1) = bits1 ⊦ bits = [], bitsand(bits, bits0) = bits0, false ∈ bits

Proof step 2 from proof add-ones-lelen (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information