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Proof step 2 from proof and-011x-neg (previous step)

bitsand(false ' + bits0, bits) = false ' + bits1, bits.first ⊦ bits = [], 2 ^ n→i(# bits0) = bits2uint(bits1) + bits2uint(bitsinvert(bits)) % 2 ^ n→i(# bits0) + 1, false ∈ bits0

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 3:
bits = boolvar + bits2, bitsand(false ' + bits0, bits) = false ' + bits1, boolvar ⊦ bits = [], 2 ^ n→i(# bits0) = bits2uint(bits1) + bits2uint(bitsinvert(bits)) % 2 ^ n→i(# bits0) + 1, false ∈ bits0

Rule argument

seq: bits ≠ [] ⊦ (boolvar ↔ bits.first) ∧ bits0 = bits.rest ↔ bits = boolvar + bits0 subst: [bits, boolvar, bits0] → [bits, boolvar, bits2] rotate: T spec: list-data inst: bitlista name: elim-list-c

Additional information

Used simplifier rules: bits ≠ [] ⊦ (boolvar ↔ bits.first) ∧ bits0 = bits.rest ↔ bits = boolvar + bits0; (elim) Used terms: bits, boolvar, bits2