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Proof step 2 from proof and-bits2int-sgn (previous step)

⊦ bits = [], bits0 = [], bits2int(bitsand(sgn(bits), bits0)) = bits2int(bitsand(bits, bits0))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ bits2int(bits) = bits2int(sgn(bits))

Rule argument

seq: ⊦ bits2int(bits) = bits2int(sgn(bits)) subst: [bits] → [bitsand(sgn(bits), bits0)] rotate: F spec: int2bits inst: name: bits2int-sgn-intro

Additional information

Used simplifier rules: and-sgn: ⊦ bits ≠ [] ∧ bits0 ≠ [] → sgn(bitsand(sgn(bits), bits0)) = sgn(bitsand(bits, bits0));% ⊦ bits2int(sgn(bits)) = bits2int(bits); Used terms: bitsand(sgn(bits), bits0)