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Proof step 3 from proof and-com (previous step)

true, ∀ bits1, bits. # bits1 < # bits0 → true → bits = [] ∨ bits1 = [] ∨ bitsand(bits, bits1) = bitsand(bits1, bits) ⊦ bits = [] ∨ bits0 = [] ∨ bitsand(bits, bits0) = bitsand(bits0, bits)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
∀ bits1, bits. # bits1 < # bits0 → true → bits = [] ∨ bits1 = [] ∨ bitsand(bits, bits1) = bitsand(bits1, bits) ⊦ bitsand(bits, bits0) = bitsand(bits0, bits), bits0 = [], bits = []

Proof step 3 from proof and-com (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information