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Proof step 1 from proof and-false (conclusion)

⊦ bits.first ∧ bits0.first ∧ bits ≠ [] ∧ bits0 ≠ [] → bitsand(bits, bits0) ≠ false ' + bits1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
bitsand(bits, bits0) = false ' + bits1, bits.first, bits0.first, false ∈ bitsand(bits, bits0) ⊦ bits0 = [], bits = []

Rule argument

Additional information

Used simplifier rules: ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ boolvar ' + bits = bits0 → boolvar ∈ bits0; (forward)