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Proof step 23 from proof and-insgn (previous step)

∀ bits1, bits, boolvar. # bits1 < # false ' → true → bits = [] ∨ bits1 = [] ∨ (boolvar ∈ bitsand(sgn(bits), bits1) ↔ boolvar ∈ bitsand(bits, bits1)) ⊦ bits = [], boolvar ∈ bitsand(sgn(bits), false ') ↔ ¬ boolvar

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 24:
⊦ bits ≠ [] ∧ bits0 = false ' → bitsand(bits, bits0) = false '

Rule argument

name: and-rec-02 rotate: F subst: [bits0, bits] → [false ', sgn(bits)]

Additional information

Used simplifier rules: ⊦ sgn(bits) = [] ↔ bits = [];% ⊦ boolvar ∈ boolvar0 ' ↔ boolvar ↔ boolvar0; Used terms: false ', sgn(bits)