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Proof step 26 from proof and-insgn (previous step)

∀ bits1, bits, boolvar. # bits1 < # true ' → true → bits = [] ∨ bits1 = [] ∨ (boolvar ∈ bitsand(sgn(bits), bits1) ↔ boolvar ∈ bitsand(bits, bits1)) ⊦ boolvar ∈ bitsand(sgn(bits), true ') ↔ boolvar ∈ bits, bits = []

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 27:
⊦ bits ≠ [] ∧ bits0 = true ' → bitsand(bits, bits0) = bits

Rule argument

name: and-rec-01 rotate: F subst: [bits0, bits] → [true ', sgn(bits)]

Additional information

Used simplifier rules: ⊦ sgn(bits) = [] ↔ bits = [];% ⊦ bits ≠ [] → (boolvar ∈ sgn(bits) ↔ boolvar ∈ bits); Used terms: true ', sgn(bits)