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Proof step 1 from proof and-one (conclusion)

⊦ bitsand(boolvar ', boolvar0 ') = (boolvar ∧ boolvar0)'

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ bits ≠ [] ∧ bits0 = true ' → bitsand(bits, bits0) = bits
Proof step 3:
¬(boolvar ' ≠ [] ∧ boolvar0 ' = true ') ⊦ bitsand(boolvar ', boolvar0 ') = (boolvar ∧ boolvar0)'

Rule argument

name: and-rec-01 rotate: F subst: [bits0, bits] → [boolvar0 ', boolvar ']

Additional information

Used simplifier rules: ⊦ boolvar ' = boolvar0 ' ↔ boolvar ↔ boolvar0; Used terms: boolvar0 ', boolvar '