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Proof step 1 from proof and-rec-06 (conclusion)

⊦ bits ≠ [] ∧ bits0 ≠ [] → bitsand(bits0 + boolvar0 ', boolvar1 ' + bits) = bitsand(bits0, boolvar1 ' + bits.butlast) + (boolvar0 ∧ bits.last)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ bits0 = [], bits = [], bitsand(bits0 + boolvar0 ', boolvar1 ' + bits) = bitsand(bits0, boolvar1 ' + bits.butlast) + (boolvar0 ∧ bits.last)'

Rule argument

Additional information

Used simplifier rules: ⊦ bits + boolvar = bits + boolvar ';