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Proof step 2 from proof and-sgn (previous step)

⊦ bits = [], bits0 = [], sgn(bitsand(sgn(bits), bits0)) = sgn(bitsand(bits, bits0))

User applied rule induction

And obtained the following new goals

Proof step 3:
true, ∀ bits1, bits. # bits1 < # bits0 → true → bits = [] ∨ bits1 = [] ∨ sgn(bitsand(sgn(bits), bits1)) = sgn(bitsand(bits, bits1)) ⊦ bits = [] ∨ bits0 = [] ∨ sgn(bitsand(sgn(bits), bits0)) = sgn(bitsand(bits, bits0))

Rule argument

indvar: # bits0 wfpred: <

Additional information

Used simplifier rules: <; (wellfounded) Used terms: # bits0