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Proof step 59 from proof and-sgn (previous step)

∀ bits1, bits. # bits1 < #(bits2 + boolvar ') → true → bits = [] ∨ bits1 = [] ∨ sgn(bitsand(sgn(bits), bits1)) = sgn(bitsand(bits, bits1)) ⊦ bits0 + true ' = bits0.first ', sgn(bits2 + boolvar ') = boolvar ', bits2 = [], bits0 = [], bits2 + boolvar ' = bits2.first ', (¬ boolvar) ∈ bits2, false ∈ bits0

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

seq: ¬ (¬ boolvar) ∈ bits ⊦ sgn(bits + boolvar ') = boolvar ' subst: [boolvar, bits] → [boolvar, bits2] rotate: F spec: bitopsaux inst: name: sgn-last-same

Additional information

Used terms: boolvar, bits2