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Proof step 3 from proof and-size-one (previous step)

# bits ≤ # bits1 ∧ bits.first, ∀ bits2, bits1, bits0. # bits2 < # bits → # bits2 ≤ # bits1 ∧ bits2.first → bits2 = [] ∨ bitsand(bits2, bits0 + bits1) = bits0 + bitsand(bits2, bits1) ⊦ bits = [] ∨ bitsand(bits, bits0 + bits1) = bits0 + bitsand(bits, bits1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
bits.first, # bits ≤ # bits1, ∀ bits2, bits1, bits0. # bits2 < # bits → # bits2 ≤ # bits1 ∧ bits2.first → bits2 = [] ∨ bitsand(bits2, bits0 + bits1) = bits0 + bitsand(bits2, bits1) ⊦ bitsand(bits, bits0 + bits1) = bits0 + bitsand(bits, bits1), bits = []

Proof step 3 from proof and-size-one (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information