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Proof step 11 from proof and-true (previous step)

¬(boolvar ' + bits1 ≠ [] ∧ boolvar0 ' + bits = true '), bitsand(boolvar ' + bits1, boolvar0 ' + bits) = true ' ⊦ boolvar0 ' + bits = true ' ∧ boolvar ' + bits1 = true ', bits1 ≠ [] ∧ bits ≠ []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
bitsand(boolvar ' + bits1, boolvar0 ' + bits) = true ' ⊦ boolvar0 ' + bits = true ', bits1 ≠ [] ∧ bits ≠ []

Rule argument

Additional information

Used simplifier rules: ⊦ boolvar ' = boolvar0 ' ↔ boolvar ↔ boolvar0;% ⊦ boolvar ' ≠ [];% ⊦ ¬ bits + bits0 ≠ [] ↔ bits = [] ∧ bits0 = [];% ⊦ bits + [] = bits;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ boolvar ' = boolvar0 ' + bits ↔ (boolvar ↔ boolvar0) ∧ bits = [];