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Proof step 18 from proof and-true (previous step)

bitsand(boolvar ' + bits1, boolvar0 ' + bits) = true ' ⊦ boolvar0 ' + bits = true ', boolvar0 ' + bits = false ', boolvar ' + bits1 = true ', bits1 ≠ [] ∧ bits ≠ []

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 19:
⊦ bits0 ≠ [] ∧ bits = false ' → bitsand(bits, bits0) = false '
Proof step 20:
¬(boolvar0 ' + bits ≠ [] ∧ boolvar ' + bits1 = false '), bitsand(boolvar ' + bits1, boolvar0 ' + bits) = true ' ⊦ boolvar0 ' + bits = true ', boolvar0 ' + bits = false ', boolvar ' + bits1 = true ', bits1 ≠ [] ∧ bits ≠ []

Rule argument

name: and-rec-04 rotate: F subst: [bits0, bits] → [boolvar0 ' + bits, boolvar ' + bits1]

Additional information

Used simplifier rules: ⊦ boolvar ' = boolvar0 ' + bits ↔ (boolvar ↔ boolvar0) ∧ bits = [];% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ boolvar ' = boolvar0 ' ↔ boolvar ↔ boolvar0; Used terms: boolvar0 ' + bits, boolvar ' + bits1