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Proof step 1 from proof and-two-08 (conclusion)

⊦ bitsand(bits + boolvar ' + true ', boolvar1 ' + false ') = bitsand(bits + boolvar, boolvar1 ') + false '

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: and-rec-08: ⊦ bitsand(bits + boolvar ' + boolvar0 ', boolvar1 ' + boolvar2 ') = bitsand(bits + boolvar ', boolvar1 ') + (boolvar0 ∧ boolvar2);% ⊦ bits + bits0 = bits + bits1 ↔ bits0 = bits1;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ bits + boolvar = bits + boolvar ';