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Proof step 2 from proof and-zerosin (previous step)

true ∈ bitsand(bits, bits0) ⊦ bits = [], bits0 = [], true ∈ bits

User applied rule induction

And obtained the following new goals

Proof step 3:
true ∈ bitsand(bits, bits0), ∀ bits1, bits0. # bits1 < # bits → true ∈ bitsand(bits1, bits0) → bits1 = [] ∨ bits0 = [] ∨ true ∈ bits1 ⊦ bits = [] ∨ bits0 = [] ∨ true ∈ bits

Rule argument

indvar: # bits wfpred: <

Additional information

Used simplifier rules: <; (wellfounded) Used terms: # bits