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Proof step 20 from proof band-011x-eq (previous step)

0 ≤ i, 0 ≤ j, 0 < j, i < j ⊦ j % (i + 1) + (1 + i - j) % (i + 1) = 0, false ∈ int2bits(i).rest

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 21:
⊦ false ∈ int2bits(j).rest ↔ ¬(∃ i. j = 2 ^ i - 1)
Proof step 22:
0 ≤ i, 0 ≤ j, 0 < j, i < j ⊦ j % (i + 1) + (1 + i - j) % (i + 1) = 0, ∀ i0. i ≠ 2 ^ i0 - 1

Rule argument

seq: ⊦ false ∈ int2bits(j).rest ↔ ¬(∃ i. j = 2 ^ i - 1) subst: [j] → [i] rotate: F spec: int2bits inst: name: int2bits-falsein-02

Additional information

Used terms: i