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Proof step 23 from proof band-011x-is-lastn (previous step)

#(boolvar ' + bits1) = #(false ' + mklist(true, i→n(i))) ∧ 1 < #(boolvar ' + bits1), int2bits(j) = bits0 + boolvar ' + bits1, # bits1 = i→n(i), 0 < i ⊦ bits2int (((boolvar ' + bits1).first ∧ (false ' + mklist(true, i→n(i))).first)' + bitsand((boolvar ' + bits1).rest, (false ' + mklist(true, i→n(i))).rest)) = bits2uint(bits1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 24:
int2bits(j) = bits0 + boolvar ' + bits1, # bits1 = i→n(i), 0 < i ⊦ bits2uint(bitsand(bits1, mklist(true, i→n(i)))) = bits2uint(bits1), bits1 = []

Rule argument

Additional information

Used simplifier rules: ⊦ # bits = 0 ↔ bits = [];% ⊦ m + n = 1 ↔ m = 0 ∧ n = 1 ∨ n = 0 ∧ m = 1;% ⊦ m + 1 ≠ 0;% ⊦ 1 < m ↔ ¬(m = 0 ∨ m = 1);% ⊦ bits2int(false ' + bits) = bits2uint(bits);% ⊦ (boolvar ' + bits).rest = bits;% ⊦ (boolvar ' + bits).first ↔ boolvar;% ⊦ m + n = n + m;% ⊦ (m + n0) + n1 = m + n0 + n1;% ⊦ m + n = m + n0 ↔ n = n0;% ⊦ # mklist(boolvar, n) = n;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ # boolvar ' = 0 +1;% ⊦ #(bits + bits0) = # bits + # bits0;