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Proof step 6 from proof band-011x-is-lastn (previous step)

i→n(i) ≤ # int2bits(j), 0 < i ⊦ i→n(i) = # int2bits(j), band(j, 2 ^ i - 1) = bits2uint(lastn(i→n(i), int2bits(j)))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
i→n(i) < # int2bits(j), 0 < i ⊦ band(j, 2 ^ i - 1) = bits2uint(lastn(i→n(i), int2bits(j))), i→n(i) = # int2bits(j)

Rule argument

Additional information

Used simplifier rules: ⊦ int2bits(j) ≠ [];% ⊦ # bits = 0 ↔ bits = [];% ⊦ m < n → n ≠ 0; (forward)% ⊦ m ≠ n → (m ≤ n ↔ m < n);