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Proof step 7 from proof band-011x-is-unsigned-03 (previous step)

¬ ( ¬ false ∈ int2bits(2 ^ n→i(# int2bits(j)) - 1).rest ∧ abs(j) ≤ 2 ^ n→i(# int2bits(2 ^ n→i(# int2bits(j)) - 1) - 2) ∧ 0 < 2 ^ n→i(# int2bits(j)) - 1) ⊦ band(j, 2 ^ n→i(# int2bits(j)) - 1) = bits2uint(int2bits(j))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ int2bits(j) ≠ [];% ⊦ # bits = 0 ↔ bits = [];% ⊦ 0 < n ↔ n ≠ 0;%0 ≤ i ⊦ (* i) < n→i(n) ↔ i→n(i) < n;% ⊦ 1 < 2 ^ i ↔ 0 < i;% ⊦ i < j - i0 ↔ i + i0 < j;% ⊦ ¬ i ≤ j ↔ j < i;% ⊦ # mklist(boolvar, n) = n;% ⊦ # boolvar ' = 0 +1;% ⊦ #(bits + bits0) = # bits + # bits0;% ⊦ ¬ false ∈ mklist(true, n);% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ (boolvar ' + bits).rest = bits;% ⊦ i→n(n→i(n)) = n;%0 ≤ i ⊦ int2bits(2 ^ i - 1) = false ' + mklist(true, i→n(i));% ⊦ 0 ≤ n→i(n);