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Proof step 12 from proof band-011x-is-unsigned-fix (previous step)

1 + i→n(i) - 2 = i→n(i) - 1, # int2bits(j) < i→n(i), 0 < i, 2 ^ n→i(1 + i→n(i) - 2) < abs(j) ⊦ band(j, 2 ^ i - 1) = bits2uint(fillsgn(i→n(i), int2bits(j))), i = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 13:
1 + i→n(i) - 2 = i→n(i) - 1, # int2bits(j) < i→n(i), 0 < i, 2 ^ n→i(i→n(i) - 1) < abs(j) ⊦ band(j, 2 ^ i - 1) = bits2uint(fillsgn(i→n(i), int2bits(j))), i = 0

Proof step 12 from proof band-011x-is-unsigned-fix (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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