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Proof step 25 from proof band-011x-is-unsigned (previous step)

0 ≤ j ∧ 0 ≤ i, abs(j) ≤ 2 ^ (i - 1), 0 < i ⊦ j % 2 ^ i = bits2uint(fillsgn(i→n(i), int2bits(j)))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 26:
0 < i, j ≤ 2 ^ (i - 1), 0 ≤ j, 0 ≤ i, 0 ≤ 2 ^ (i - 1) ⊦ j % 2 ^ i = j

Rule argument

Additional information

Used simplifier rules: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward)% ⊦ 0 ≤ i → abs(i) = i;% ⊦ 0 ≤ j → bits2uint(fillsgn(n, int2bits(j))) = j;