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Proof step 21 from proof band-011x-neg-03 (previous step)

2 + i - j = (1 - j) + i + 1, 0 ≤ i, 0 < j, i + 1 < j ⊦ (1 - j) % (i + 1) = (2 + i - j) % (i + 1), false ∈ int2bits(i).rest

User applied rule insert equation

And obtained the following new goals

Proof step 22:
0 ≤ i, 0 < j, i + 1 < j ⊦ (1 - j) % (i + 1) = ((1 - j) + i + 1) % (i + 1), false ∈ int2bits(i).rest

Rule argument

pos: left 1 flags: discard

Additional information