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Proof step 25 from proof band-associativity (previous step)

⊦ bitsand(sgn(bitsand(int2bits(i), int2bits(i0))), int2bits(j)) = [], sgn(bitsand(int2bits(i), bitsand(int2bits(i0), int2bits(j)))) = sgn(bitsand(bitsand(int2bits(i), int2bits(i0)), int2bits(j)))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 26:
⊦ bits ≠ [] ∧ bits0 ≠ [] ∧ bits1 ≠ [] → bitsand(bits, bitsand(bits0, bits1)) = bitsand(bitsand(bits, bits0), bits1)

Rule argument

name: and-ass rotate: F subst: [bits1, bits0, bits] → [int2bits(j), int2bits(i0), int2bits(i)]

Additional information

Used simplifier rules: ⊦ int2bits(j) ≠ []; Used terms: int2bits(j), int2bits(i0), int2bits(i)