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Proof step 10 from proof band-max (previous step)

i < bits2int(bitsand(int2bits(i), int2bits(j))), 0 ≤ i, 0 < bits2int(bitsand(int2bits(i), int2bits(j))), i ≤ 1, ∀ i0, j. i→n(i0) < i→n(i) → i0 < bits2int(bitsand(int2bits(i0), int2bits(j))) ∧ 0 ≤ i0 → false ⊦

User applied rule cut formula

And obtained the following new goals

Proof step 11:
i = 0, i < bits2int(bitsand(int2bits(i), int2bits(j))), 0 ≤ i, 0 < bits2int(bitsand(int2bits(i), int2bits(j))), i ≤ 1, ∀ i0, j. i→n(i0) < i→n(i) → i0 < bits2int(bitsand(int2bits(i0), int2bits(j))) ∧ 0 ≤ i0 → false ⊦
Proof step 14:
i < bits2int(bitsand(int2bits(i), int2bits(j))), 0 ≤ i, 0 < bits2int(bitsand(int2bits(i), int2bits(j))), i ≤ 1, ∀ i0, j. i→n(i0) < i→n(i) → i0 < bits2int(bitsand(int2bits(i0), int2bits(j))) ∧ 0 ≤ i0 → false ⊦ i = 0

Rule argument

fma: i = 0

Additional information

Used formulas: i = 0