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Proof step 23 from proof band-max (previous step)

¬(1 < #(false ' + true ') ∧ 1 < # int2bits(j)), 1 < bits2int(bitsand(false ' + true ', int2bits(j))), 0 < bits2int(bitsand(false ' + true ', int2bits(j))), ∀ i0, j. i→n(i0) < i→n(1) → i0 < bits2int(bitsand(int2bits(i0), int2bits(j))) ∧ 0 ≤ i0 → false ⊦ j = ~1, j = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ bits + [] = bits;% ⊦ boolvar + bits = boolvar ' + bits;% ⊦ int2bits(j).first ↔ j < 0;% ⊦ # bits = 1 ↔ bits = bits.first + [];% ⊦ int2bits(j) ≠ [];% ⊦ # bits = 0 ↔ bits = [];% ⊦ 1 < m ↔ ¬(m = 0 ∨ m = 1);% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ # boolvar ' = 0 +1;% ⊦ #(bits + bits0) = # bits + # bits0;