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Proof step 6 from proof band-max (previous step)

i < bits2int(bitsand(int2bits(i), int2bits(j))) ∧ 0 ≤ i, ∀ i0, j. i→n(i0) < i→n(i) → i0 < bits2int(bitsand(int2bits(i0), int2bits(j))) ∧ 0 ≤ i0 → false ⊦ false

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
i < bits2int(bitsand(int2bits(i), int2bits(j))), 0 ≤ i, 0 < bits2int(bitsand(int2bits(i), int2bits(j))), ∀ i0, j. i→n(i0) < i→n(i) → i0 < bits2int(bitsand(int2bits(i0), int2bits(j))) ∧ 0 ≤ i0 → false ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ i ≤ j ∧ j < j0 → i < j0; (forward)