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Proof step 91 from proof band-max (previous step)

¬(i % 2 = 1 ∧ j % 2 = 1) ∧ bitsand(int2bits(i / 2), int2bits(j / 2)) ≠ [], 0 < i, 1 < i, 0 ≤ i, i < bits2int(bitsand(int2bits(i / 2), int2bits(j / 2))) * 2, 1 < j, 0 < j, 1 < bits2int(bitsand(int2bits(i / 2), int2bits(j / 2))) * 2, 0 < bits2int(bitsand(int2bits(i / 2), int2bits(j / 2))) * 2, ∀ i0, j. i→n(i0) < i→n(i) → i0 < bits2int(bitsand(int2bits(i0), int2bits(j))) ∧ 0 ≤ i0 → false ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: and-notempty-09: ⊦ bitsand(int2bits(i), int2bits(i0)) ≠ [];% ⊦ i < j ∧ 0 < i → 0 < j ∧ 1 < j; (forward)% ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward)% ⊦ 0 < i → (0 < i * j ↔ 0 < j);% ⊦ i * j = j * i;% ⊦ i * j * j0 = (i * j) * j0;% ⊦ 0 < i ∧ 0 ≤ j → ((* j) < (* i) * i0 ↔ j / i < i0);