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Proof step 20 from proof band-min-01 (previous step)

# int2bits(i) < # bitsand(int2bits(j), int2bits(i)), # int2bits(i) < # int2bits(j), bits2int(bitsand(int2bits(j), int2bits(i))) < i0, i0 + 2 ^ n→i(# int2bits(i)) ≤ 0, i0 + 2 ^ n→i(# int2bits(j)) ≤ 0, i < 0, j < 0, # int2bits(j) < # bitsand(int2bits(j), int2bits(i)), 2 ^ n→i(# int2bits(j)) + bits2int(bitsand(int2bits(j), int2bits(i))) < 0, # int2bits(i) + 1 < # bitsand(int2bits(j), int2bits(i)) ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 21:
⊦ bits0.first ∧ # bits0 ≤ # bits ∧ bits0 ≠ [] → # bitsand(bits, bits0) = # bits

Rule argument

name: bitsand-len-true rotate: F subst: [bits0, bits] → [int2bits(i), int2bits(j)]

Additional information

Used simplifier rules: ⊦ m < n → ¬ n < m;% ⊦ ¬ m ≤ n ↔ n < m;% ⊦ int2bits(j) ≠ [];% ⊦ j < 0 → int2bits(j).first;% ⊦ m < n → m ≤ n;% ⊦ ¬ n < n; Used terms: int2bits(i), int2bits(j)