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Proof step 22 from proof band-min-01 (previous step)

bits2int(bitsand(int2bits(i), int2bits(j))) < i0, i0 + 2 ^ n→i(# int2bits(i)) ≤ 0, i0 + 2 ^ n→i(# int2bits(j)) ≤ 0, i < 0, j < 0 ⊦ # int2bits(i) < # int2bits(j)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 23:
bits2int(bitsand(int2bits(i), int2bits(j))) < i0, i0 + 2 ^ n→i(# int2bits(i)) ≤ 0, i0 + 2 ^ n→i(# int2bits(j)) ≤ 0, i < 0, j < 0, # int2bits(j) ≤ # int2bits(i) ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ m < n ↔ n ≤ m;