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Proof step 3 from proof band-minus-one (previous step)

⊦ bits2int(bitsand(int2bits(~1), int2bits(i))) = i

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: bitsand-true: ⊦ bitsand(true ', int2bits(i)) = int2bits(i);% ⊦ bits2int(int2bits(i)) = i;% ⊦ int2bits(~1) = true ';