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Proof step 11 from proof band-mod256-neg (previous step)

¬ ~255 + i % 256 < 0, 0 < i % 256, 127 < i % 256, 0 ≤ i, 256 ≤ abs(~255 + i % 256) ⊦ 255 + (~255 + i % 256) % 256 = i % 256

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
0 < i % 256, 127 < i % 256, 0 ≤ i, 511 ≤ i % 256, 255 ≤ i % 256 ⊦ 255 + (~255 + i % 256) % 256 = i % 256

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ i < j ↔ j ≤ i;% ⊦ i + (* j) < (* j0) ↔ i < j0 - j;% ⊦ i + j = j + i;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ (* j) ≤ i0 + (* j0) ↔ j - j0 ≤ i0;% ⊦ ¬ j < 0 → abs(j) = j;