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Proof step 14 from proof band-mod256-neg (previous step)

0 < 256 → i % 256 < 256, 0 < i % 256, 127 < i % 256, 0 ≤ i, 511 ≤ i % 256, 255 ≤ i % 256 ⊦ 255 + (~255 + i % 256) % 256 = i % 256

User applied rule case distinction

And obtained the following new goals

Proof step 15:
i % 256 < 256, 0 < i % 256, 127 < i % 256, 0 ≤ i, 511 ≤ i % 256, 255 ≤ i % 256 ⊦ 255 + (~255 + i % 256) % 256 = i % 256

Rule argument

pos: left 1

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