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Proof step 8 from proof band-mod256-neg (previous step)

¬ abs(~255 + i % 256) < 256, 0 < i % 256, 127 < i % 256, 0 ≤ i ⊦ 255 + (~255 + i % 256) % 256 = i % 256

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
0 < i % 256, 127 < i % 256, 0 ≤ i, 256 ≤ abs(~255 + i % 256) ⊦ 255 + (~255 + i % 256) % 256 = i % 256

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ i < j ↔ j ≤ i;