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Proof step 3 from proof band-one-is-mod2 (previous step)

¬(0 ≤ i ∧ ¬ false ∈ int2bits(1).rest ∧ 0 ≤ 1) ⊦ 0 ≤ i → (band(i, 1) = 1 ↔ i % 2 = 1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
false ∈ int2bits(1).rest, 0 ≤ i ⊦ band(i, 1) = 1 ↔ i % 2 = 1

Rule argument

Additional information

Used simplifier rules: forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs%lels-04: ⊦ i ≤ j → (¬ ¬ j < i ↔ false); from specification int-abs%lels-01: ⊦ ¬ i ≤ j ↔ j < i; from specification int-abs