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Proof step 1 from proof bitsand-app-false (conclusion)
⊦ # bits1 ≤ # bits0 ∧ bits1 ≠ [] ∧ ¬ bits1.first → bitsand(bits + bits0, bits1) = bitsand(bits0, bits1)
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 2
:
# bits1 ≤ # bits0 ⊦ bits1 = [], bitsand(bits + bits0, bits1) = bitsand(bits0, bits1), bits1.first
Rule argument
Additional information