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Proof step 5 from proof bitsand-app-false (previous step)

# bits2 < # bits0, ∀ bits, bits0, bits1. # bits1 < # bits2 → # bits1 < # bits0 → bitsand(bits + bits0, false ' + bits1) = bitsand(bits0, false ' + bits1) ∨ bits0 = [] ⊦ bitsand(bits + bits0, false ' + bits2) = bitsand(bits0, false ' + bits2) ∨ bits0 = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
# bits2 < # bits0, ∀ bits, bits0, bits1. # bits1 < # bits2 → # bits1 < # bits0 → bitsand(bits + bits0, false ' + bits1) = bitsand(bits0, false ' + bits1) ∨ bits0 = [] ⊦ bits0 = [], bitsand(bits + bits0, false ' + bits2) = bitsand(bits0, false ' + bits2)

Proof step 5 from proof bitsand-app-false (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information