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Proof step 46 from proof bitsand-app-zeros (
previous step
)
⊦ ¬ true ∈ bits ∧ bits1 ≠ [] → (true ∈ bitsand(bits + false ' + bits0, bits1) ↔ true ∈ bitsand(false ' + bits0, bits1))
Lemma
bitsand-onein