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Proof step 53 from proof bitsand-app-zeros (previous step)

¬(true ∈ bitsand(bits + false ' + bits3, false ' + bits4) ∧ false ∈ bitsand(bits + false ' + bits3, false ' + bits4)), false ∈ bitsand(false ' + bits3, false ' + bits4), true ∈ bitsand(false ' + bits3, false ' + bits4), ∀ bits0, bits, bits2. # bits2 < #(bits4 + boolvar0 ') → true → sgn(bitsand(bits + false ' + bits0, false ' + bits2)) = sgn(bitsand(false ' + bits0, false ' + bits2)) ∨ true ∈ bits ⊦ sgn(bitsand(bits + false ' + bits3, false ' + bits4) + (boolvar ∧ boolvar0)') = sgn(bitsand(false ' + bits3, false ' + bits4)) + (boolvar ∧ boolvar0)', true ∈ bits

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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