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Proof step 3 from proof bitsand-app (previous step)

# bits = # bits1, ∀ bits2, bits0, bits, bits3. # bits3 < # bits1 → # bits = # bits3 → bits0 = [] ∨ bits2 = [] ∨ bits = [] ∨ bitsand(bits0 + bits, bits2 + bits3) = bitsand(bits0, bits2) + bitsand(bits, bits3) ⊦ bits0 = [] ∨ bits2 = [] ∨ bits = [] ∨ bitsand(bits0 + bits, bits2 + bits1) = bitsand(bits0, bits2) + bitsand(bits, bits1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
# bits = # bits1, ∀ bits2, bits0, bits, bits3. # bits3 < # bits1 → # bits = # bits3 → bits0 = [] ∨ bits2 = [] ∨ bits = [] ∨ bitsand(bits0 + bits, bits2 + bits3) = bitsand(bits0, bits2) + bitsand(bits, bits3) ⊦ bitsand(bits0 + bits, bits2 + bits1) = bitsand(bits0, bits2) + bitsand(bits, bits1), bits = [], bits2 = [], bits0 = []

Proof step 3 from proof bitsand-app (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information