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Proof step 19 from proof bitsand-cast-01 (previous step)

¬(# bits0 ≤ # bits1 ∧ bits0 ≠ [] ∧ ¬ bits0.first) ⊦ bits2 = [], bits2 + bits1 = [], bits0 = [], lastn(# bits1, fillsgn(# bits1, bitsand(bits1, bits0))) = lastn(# bits1, fillsgn(# bits1, bitsand(bits2 + bits1, bits0)))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ m ≤ n ↔ n < m;