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Proof step 24 from proof bitsand-cast-01 (previous step)

⊦ ¬ # bits1 < # bits0, bits2 = [], bits2 + bits1 = [], bits0 = [], lastn(# bits1, fillsgn(# bits1, bitsand(bits1, bits0))) = lastn(# bits1, fillsgn(# bits1, bitsand(bits2 + bits1, bits0))), ¬ # bits1 < # bits0 ∧ ¬ bits0.first, ¬ # bits1 < # bits0 ∧ bits0.first

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 25:
# bits1 < # bits0 ⊦ lastn(# bits1, fillsgn(# bits1, bitsand(bits1, bits0))) = lastn(# bits1, fillsgn(# bits1, bitsand(bits2 + bits1, bits0))), bits0 = [], bits2 + bits1 = [], bits2 = []

Rule argument

Additional information

Used simplifier rules: ⊦ # bits = 0 ↔ bits = [];% ⊦ m < n → n ≠ 0; (forward)