[Imprint][Data Privacy Statement][E-Mail]

View long theorem info. View the proof. Back to main index. View the specification. View theorem base summary, View theorem base listing, the used properties by spec, the dependency list, the symbol table,

Proof step 31 from proof bitsand-cast-01 (previous step)

# bits = # bits1 ⊦ bits2 + bits1 = [], bits2 = [], bits3 + bits = [], bits1 = [], bits3 = [], lastn(# bits1, fillsgn(# bits1, bitsand(bits3 + bits, bits1))) = lastn(# bits1, fillsgn(# bits1, bitsand(bits2, bits3) + bitsand(bits1, bits)))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 32:
⊦ n ≤ # bits → fillsgn(n, bits) = bits
Proof step 33:
¬ # bits1 ≤ #(bitsand(bits2, bits3) + bitsand(bits1, bits)), # bits = # bits1 ⊦ bits2 + bits1 = [], bits2 = [], bits3 + bits = [], bits1 = [], bits3 = [], lastn(# bits1, fillsgn(# bits1, bitsand(bits3 + bits, bits1))) = lastn(# bits1, fillsgn(# bits1, bitsand(bits2, bits3) + bitsand(bits1, bits)))
Proof step 36:
# bits1 ≤ #(bitsand(bits2, bits3) + bitsand(bits1, bits)), # bits = # bits1 ⊦ bits2 + bits1 = [], bits2 = [], bits3 + bits = [], bits1 = [], bits3 = [], lastn(# bits1, fillsgn(# bits1, bitsand(bits3 + bits, bits1))) = lastn(# bits1, bitsand(bits2, bits3) + bitsand(bits1, bits))

Rule argument

seq: ⊦ n ≤ # bits → fillsgn(n, bits) = bits subst: [bits, n] → [bitsand(bits2, bits3) + bitsand(bits1, bits), # bits1] rotate: F spec: bitopsaux inst: name: fillsgn-longer

Additional information

Used terms: bitsand(bits2, bits3) + bitsand(bits1, bits), # bits1