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Proof step 61 from proof bitsand-cast-01 (previous step)

# bits1 ≤ # bits ∧ bits1 ≠ [] ∧ ¬ bits1.first, # bits1 ≤ # bitsand(bits, bits1), # bits = # bits1, # bits1 = # bitsand(bits1, bits) ⊦ lastn(# bits1, bitsand(bits, bits1)) = bitsand(bits1, bits), bits3 = [], bits1 = [], bits3 + bits = [], bits2 = [], bits2 + bits1 = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 62:
# bits1 = # bitsand(bits1, bits), # bits = # bits1 ⊦ bits1 = [], bits2 + bits1 = [], bits2 = [], bits3 + bits = [], bits3 = [], lastn(# bits1, bitsand(bits, bits1)) = bitsand(bits1, bits), bits1.first

Rule argument

Additional information

Used simplifier rules: bitsand-len-false: ⊦ ¬ bits0.first ∧ # bits0 ≤ # bits ∧ bits0 ≠ [] → # bitsand(bits, bits0) = # bits0;% ⊦ m ≤ m;