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Proof step 69 from proof bitsand-cast-01 (previous step)

# bits0 ≤ # bits1 ∧ bits0 ≠ [] ∧ bits0.first ⊦ bits2 = [], bits2 + bits1 = [], bits0 = [], lastn(# bits1, fillsgn(# bits1, bitsand(bits1, bits0))) = lastn(# bits1, fillsgn(# bits1, bits2 + bitsand(bits1, bits0))), ¬ # bits1 < # bits0 ∧ ¬ bits0.first

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 70:
# bits0 ≤ # bits1, bits0.first ⊦ bits2 = [], bits2 + bits1 = [], lastn(# bits1, fillsgn(# bits1, bitsand(bits1, bits0))) = lastn(# bits1, fillsgn(# bits1, bits2 + bitsand(bits1, bits0))), bits0 = []

Rule argument

Additional information

Used simplifier rules: ⊦ m ≤ n → (n < m ↔ false);