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Proof step 1 from proof bitsand-cast-04 (conclusion)

⊦ # bits0 ≤ n ∧ ¬ bits0.first ∧ bits ≠ [] ∧ bits0 ≠ [] → sgn(bitsand(lastn(n, fillsgn(n, bits)), bits0)) = sgn(bitsand(bits, bits0))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information