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Proof step 3 from proof bitsand-cast-05 (previous step)

bits0 = boolvar + bits1, # bits0 ≤ n + 1 ⊦ sgn(bitsand(lastn(n, fillsgn(n, bits)), bits0)) = sgn(bitsand(bits, bits0)), bits0 = [], bits = [], n = 0, boolvar

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
# bits1 ≤ n ⊦ bits = [], n = 0, sgn(bitsand(lastn(n, fillsgn(n, bits)), false ' + bits1)) = sgn(bitsand(bits, false ' + bits1))

Rule argument

Additional information

Used simplifier rules: ⊦ m + n = n + m;% ⊦ (m + n0) + n1 = m + n0 + n1;% ⊦ m + n ≤ m + n0 ↔ n ≤ n0;% ⊦ # boolvar ' = 0 +1;% ⊦ #(bits + bits0) = # bits + # bits0;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ boolvar ' + bits ≠ [];% ⊦ boolvar + bits = boolvar ' + bits;